10. Fail-over allocator

10.1. Introduction

.intro: This is the design of the fail-over allocator, a data structure for the management of address ranges.

.readership: This document is intended for any MPS developer.

.source: design.mps.land, design.mps.poolmvt, design.mps.poolmvff.

.overview: The fail-over allocator combines two land instances. It stores address ranges in one of the lands (the primary) unless insertion fails, in which case it falls back to the other (the secondary). The purpose is to be able to combine two lands with different properties: with a CBS for the primary and a Freelist for the secondary, operations are fast so long as there is memory to allocate new nodes in the CBS, but operations can continue using the Freelist when memory is low.

10.2. Interface

.land: The fail-over allocator is an implementation of the land abstract data type, so the interface consists of the generic functions for lands. See design.mps.land.

10.2.1. Types

typedef struct FailoverStruct *Failover

.type.failover: The type of fail-over allocator structures. A FailoverStruct is typically embedded in another structure.

10.2.2. Classes

.class: CLASS(Failover) is the fail-over allocator class, a subclass of CLASS(Land) suitable for passing to LandInit().

10.2.3. Keyword arguments

When initializing a fail-over allocator, LandInit() requires these two keyword arguments:

  • FailoverPrimary (type Land) is the primary land.

  • FailoverSecondary (type Land) is the secondary land.

10.3. Implementation

.impl.assume: The implementation assumes that the primary is fast but space-hungry (a CBS) and the secondary is slow but space-frugal (a Freelist). This assumption is used in the following places:

.impl.assume.flush: The fail-over allocator attempts to flush the secondary to the primary before any operation, in order to benefit from the speed of the primary wherever possible. In the normal case where the secondary is empty this is cheap.

.impl.assume.delete: When deletion of a range on the primary fails due to lack of memory, we assume that this can only happen when there are splinters on both sides of the deleted range, one of which needs to be allocated a new node (this is the case for CBS), and that therefore the following procedure will be effective: first, delete the enclosing range from the primary (leaving no splinters and thus requiring no allocation), and re-insert the splinters (failing over to the secondary if necessary).